Operator on Blog - uTIcARdI

os.path.join() or os.sep.join()?

Tue, 23 Jul 2019 00:00:00 +0000

There are two functions join a full path. E.g.: In drive: C:

|- test
| |- test.xt

os.path.join

import os
fullpath = os.path.join('c:', 'test', 'test.txt')

Output on windows:

c:test\test.txt

Output on Mac OS

c:/test/test.txt

os.sep.join

import os
fullpath = os.sep.join(['c:', 'test', 'test.txt'])

Output on windows:

c:\test\test.txt

Output on Mac OS

c:/test/test.txt

From the outputs, you can see the difference: os.path.join() doesn’t work as expected on windows.

Further verification:

with open(fullpath) as test:
 test.read()

Run with error:

 with open(fullpath) as test:
FileNotFoundError: [Errno 2] No such file or directory: 'c:test\\test.txt'

Sat, 09 Feb 2019 00:00:00 +0000

Read a block of pseudo Python code like

comA = zip(lsA, lsB)
comB = zip(*comA)

then made a try to see how * works:

1
2
3
4
5
6
7
8


a = [1, 2, 3]
b = [4, 5, 6]
c = zip(a,b)
for j in c:
print(j)
d = zip(*c)
for i in d:
print(i)

Fri, 21 Dec 2018 00:00:00 +0000

Here is the data:

testdata = {
 'a' : 1,
 'b': 2
}

There are two ways to pass the data to a function

Passing the data to the function

def loop(data):
 for key, value in data.items():
 print(key, value)

loop(testdata)

Passing the data with operator: **

def loopStar(**kwargs):
 for key, value in kwargs.items():
 print(key, value)

loopStar(**testdata)